5y^2-3y+1=0

Solution for 5y^2-3y+1=0 equation:

Simplifying
5y2 + -3y + 1 = 0

Reorder the terms:
1 + -3y + 5y2 = 0

Solving
1 + -3y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + -0.6y + y2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + -0.6y + -0.2 + y2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + -0.6y + y2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + -0.6y + y2 = 0 + -0.2
-0.6y + y2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
-0.6y + y2 = -0.2

The y term is -0.6y.  Take half its coefficient (-0.3).
Square it (0.09) and add it to both sides.

Add '0.09' to each side of the equation.
-0.6y + 0.09 + y2 = -0.2 + 0.09

Reorder the terms:
0.09 + -0.6y + y2 = -0.2 + 0.09

Combine like terms: -0.2 + 0.09 = -0.11
0.09 + -0.6y + y2 = -0.11

Factor a perfect square on the left side:
(y + -0.3)(y + -0.3) = -0.11

Can't calculate square root of the right side.

The solution to this equation could not be determined.